a[n + 1] = a[n]/(2*a[n] - 3), a[1] = 1 + I なる 漸化式を解き (解の例; {1 + I, 1/5 - (3 I)/5, 1/41 + (9 I)/41, 1/365 - (27 I)/365, 1/3281 + (81 I)/3281, 1/29525 - (243 I)/29525, 1/265721 + (729 I)/265721, 1/2391485 - (2187 I)/2391485, 1/215…

c;46656 x^10 y^2-46656 x^10+233280 x^8 y^4+21600 x^8 y^3-373248 x^8 y^2-23328 x^8 y+139968 x^8+469685 x^6 y^6+10800 x^6 y^5-1029807 x^6 y^4-25920 x^6 y^3+700083 x^6 y^2+11664 x^6 y-140697 x^6+466560 x^4 y^8-43200 x^4 y^7-1307868 x^4 y^6+42…